ABC367 整理

cnm的ATcoder把我号封了，他个MXY

A：

水， if, else就可以做

判断这个数是否在范围内

code:

#include<bits/stdc++.h>
using namespace std;
int main(void){
    double a,b,c;
    cin>>a>>b>>c;
    c+=0.5;
    if(a>b)
	{
        if(a>c and c>b)
		{
            cout<<"Yes";
        }
		else
		{
            cout<<"No";
        }
    }
	else
	{
        if(a<c and c<b)
		{
            cout<<"No";
        }
		else
		{
            cout<<"Yes";
        }
    }
}

B：

考察 cout 的用法

读入完直接cout

#include <bits/stdc++.h>

using namespace std;

int read() 
{
  int x = 0, w = 1;
  char ch = 0;
  while (ch < '0' || ch > '9') 
  {
    if (ch == '-') w = -1;
    ch = getchar();
  }
  while (ch >= '0' && ch <= '9')
  {
    x = x * 10 + (ch - '0');
    ch = getchar();
  }
  return x * w;
}

#define endl '\n'

#define TRACE 1
#define tcout TRACE && cout

#define fst ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);

#define int long long

const int P = 998244353;
const int Base = 3221225477;
const int INF = 0x3f3f3f3f3f3f3f3f;

const int N = 1e6 + 10, M = 2e6 + 10;
signed main()
{
	double a;
	cin >> a;
	cout << a;
	return 0;
}

C:

搜索。。。。。。。。

我觉的是循环嵌套 + 递归

code:

你猜