- 对标矫正
T3500对标矫正--难题解答
- 2022-8-6 10:54:49 @
其实很简单??!!
```
int main ()
{
int a=10, b=2, c = 2, d = 10;
cin >> a >> b >> d;
for ( int i = 0; i < d; i++ )
{
cin >> c;
if ( a == c ) cout << a << ' ';
if ( b != c ) cout << b << ' ';
if ( c % 3 != 0 ) cout << c << ' ';
if ( a != c && b == c && c % 3 == 0 ) cout << "NO" << ' ';
cout << endl;
a++;
b += 2;
}
}
```
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Information
- ID
- 8
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- (None)
- # Submissions
- 6
- Accepted
- 4
- Uploaded By