- 对标矫正
- T3500对标矫正--难题解答
- @ 2022-8-6 10:54:49
其实很简单??!!
```
int main  ()
{
	int a=10, b=2, c = 2, d = 10;
	cin >> a >> b >> d;
	for ( int i = 0; i < d; i++ )
	{
		cin >> c;
		if ( a == c )  cout << a  << ' ';
		if ( b != c )  cout << b << ' ';
		if ( c % 3 != 0 )  cout << c << ' ';
		if ( a != c && b == c && c % 3 == 0 )  cout << "NO" << ' ';
		cout << endl;
		a++;
		b += 2;
	}
}
```
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            Information
- ID
- 8
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- (None)
- # Submissions
- 6
- Accepted
- 4
- Uploaded By
 
      